针对小型展览室的空调解决方案，小型展览室的特点为艺术品场所，小型展览室无大量发热设备，小型展览室内会限制参观人员的人数。根据小型展览室的特点，空调选型推荐如下：HIMOD Q14机型。
This is a solution of A/C for a small exhibition room. The characteristic of the small exhibition room is the demonstration place for art, and there is a small amount of equipment. It will limit the number of visitors. According to the characteristics of the space for the small exhibition room, the selection of model is recommended as HIMOD Q14.
经济效益评估：(Economic Evaluation)
This is a solution of A/C for a small exhibition room. The characteristic of the small exhibition room is the demonstration place for art, and there is a small amount of equipment. It will limit the number of visitors. According to the characteristics of the space for the small exhibition room, the selection of model is recommended as HIMOD Q14.
经济效益评估：(Economic Evaluation)
- 该小型展览室需安装空调面积总计100平方米左右，有少量发热设备，对温湿控制及节能有较高的要求，依据实际情况每平米所需制冷量平均按400W计算，总需求40KW制冷量。
The total area is of about 100 square meters for the small exhibition room, and there is a small amount of heat source, and it highly requires the temperature and humidity control and energy saving features. Required cooling capacity per square meter on average calculated based on the actual situation according to 400W, the total demand for cooling capacity is of 40KW.
- 要满足该项目40KW的制冷量，需使用HIMOD Q14机组1套装机。
To meet the cooling capacity of 40KW, this project is needed to use one set of unit (HIMOD Q14).
- 经济效益对比估算：传统空调满足40KW制冷量的输入功率至少为13.5KW左右，而HIMOD Q14机组1套主机的输入功率合计为8.37KW，主机部分省电38%，全年共计节省电费0.98万元以上。(按1年运行8个月，1月运行30天，1天运行8小时，用电按1元1度计算)
Comparison of economic benefit estimation: the traditional air-conditioning input power (40KW cooling capacity) is at least about 13.5KW, and the HIMOD Q14 input power per set is of 8.37KW. The energy saving is up to 38%. The annual saving is more than 9800 CNY. (According to 8 months per year, 30 days per month, 8 hours per day of operation, electricity by 1 CNY/1 degree calculation)
精密空调 机房精密空调